A thin uniform wire is bent to form the two equal sides $AB$ and $AC$ of triangle $ABC$, where $AB = AC = 5\,cm.$ The third side $BC$, of length $6\,cm,$ is made from  uniform wire of twice the density of the first. The distance of centre of mass from $A$ is

827-93

  • A

    $\frac{34}{11} \,cm$

  • B

    $\frac{11}{34} \,cm$

  • C

    $\frac{34}{9} \,cm$

  • D

    $\frac{11}{45} \,cm$

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